![]() ![]() We could approach the problem as follows. When picking the first pair of cities to connect. Moves would be repeatedly picking the most profitable connection from S.Ī more sophisticated strategy would take into account the restriction that new track must connect to existing track Call this restricted set of connections S. Move, we can pick any connection, but on subsequent moves, we are restricted to connections involving at least oneĬity we have already connected to. The simplest strategy for building track would be starting with most profitable connection. There is a public domain java matrix package available at. supply and demand at a station could be represented by n * 1 matrices and cargo converted by an n * n matrix Implementation Note: a natural way to analyze supply and demand and cargo conversions would be using matrix algebra.Į.g. Profitability = (Cargo supplied by A and demanded by B + Cargo supplied by B and demanded by A) / Distance between A and B. Lets assume the profitability of a line between 2 cities, A and B is given by the following condition. Third, not too much track will be wasted.ĭeciding the order in which to connect cities Second, we can get from any city to any other city. First, everyĬity is connected to its nearest neighbour. We can now construct a graph from the values remaining in the table. | “New players can’t join a game in progress.” | When the next button is pressed.įor every pair of cities i, j
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